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Suppose three real numbers `a`, `b`, `c` are in `G.P.` Let `z=(a+ib)/(c-ib)`. Then

A

`z=(ib)/(c )`

B

`z=(ia)/(b)`

C

`z=(ia)/(c )`

D

`z=0`

Text Solution

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The correct Answer is:
A, B
`(a,b)` Let `r` be the common ratio of `G.P.a,b,c` we have
`:.z=((a)/(b)+i)/((c )/(b)-i)=((1)/(r )+i)/(r-i)=(i)/(r )`
`z=(ib)/(c )` or `(ia)/(b)`
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