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In a game of chance a player throws a pair of dice and scores points equal to the difference between the numbers on the two dice. Winner is the person who scores exactly `5` points more than his opponent. If two players are playing this game only one time, then the probability that neither of them wins to

A

`(1)/(54)`

B

`(1)/(108)`

C

`(53)/(54)`

D

`(107)/(108)`

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To solve the problem step by step, let's break down the process of determining the probability that neither player wins in the game of chance involving two players throwing a pair of dice. ### Step 1: Understand the Game Rules In this game, each player rolls a pair of dice, and they score points equal to the absolute difference between the numbers on the two dice. A player wins if they score exactly 5 points more than their opponent. ### Step 2: Calculate Possible Outcomes for One Player When rolling two dice, the possible outcomes for the difference between the two numbers can be calculated. The possible differences (D) can be: - D = 0 (when both dice show the same number) - D = 1 (e.g., (1,2), (2,1)) - D = 2 (e.g., (1,3), (3,1)) - D = 3 (e.g., (1,4), (4,1)) - D = 4 (e.g., (1,5), (5,1)) - D = 5 (e.g., (1,6), (6,1)) The only differences that can lead to a win for Player A or Player B are when one player scores 5 points more than the other. The only way to achieve a difference of 5 is if one player rolls a (1,6) or (6,1). ### Step 3: Count Winning Combinations For Player A to win, they must roll a difference of 5, which can happen in 2 ways: 1. Player A rolls (1,6) 2. Player A rolls (6,1) For Player B, they can roll any combination that results in a difference of 0, 1, 2, 3, or 4, but not 5. The total number of outcomes for Player B that do not result in a difference of 5 is calculated by considering all possible outcomes (36) minus the winning outcomes for Player A. ### Step 4: Total Winning Outcomes The total number of outcomes where either Player A or Player B wins can be calculated as: - Player A wins in 2 ways (as calculated above). - Player B can win in similar ways, leading to a total of 4 winning combinations (2 for A and 2 for B). ### Step 5: Calculate Total Outcomes The total number of outcomes when both players roll the dice is: - Total outcomes = 6 (sides of die) × 6 (sides of die) = 36. ### Step 6: Calculate Outcomes Where Neither Wins To find the outcomes where neither player wins, we can subtract the total winning outcomes from the total outcomes: - Total outcomes where neither wins = Total outcomes - Winning outcomes = 36 - 4 = 32. ### Step 7: Calculate the Probability The probability that neither player wins is given by the ratio of the number of outcomes where neither wins to the total outcomes: - Probability = (Number of outcomes where neither wins) / (Total outcomes) = 32 / 36 = 8 / 9. ### Final Answer Thus, the probability that neither player wins is **8/9**. ---

To solve the problem step by step, let's break down the process of determining the probability that neither player wins in the game of chance involving two players throwing a pair of dice. ### Step 1: Understand the Game Rules In this game, each player rolls a pair of dice, and they score points equal to the absolute difference between the numbers on the two dice. A player wins if they score exactly 5 points more than their opponent. ### Step 2: Calculate Possible Outcomes for One Player When rolling two dice, the possible outcomes for the difference between the two numbers can be calculated. The possible differences (D) can be: - D = 0 (when both dice show the same number) ...
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