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5 players of equal strength play one eac...

`5` players of equal strength play one each with each other. `P(A)=` probability that at least one player wins all matches he (they) play. `P(B)=` probability that at least one player losses all his (their) matches.

A

`P(A)=(5)/(16)`

B

`P(B)=(7)/(16)`

C

`P(AnnB)=(5)/(32)`

D

`P(AuuB)=(15)/(32)`

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
`(a,b,d)` `P(A)=("^(5)C_(1)2^(6))/(2^(10))=(5)/(16)`, `P(B)=('^(5)C_(1)2^(6))/(2^(10))=(5)/(16)`
`P(AnnB)=("^(5)C_(2)xx2xx2^(3))/(2^(10))=(5)/(32)`
`implies P(AuuB)=(15)/(32)`
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