The records of a hospital show that `10%` of the cases of a certain disease are fatal. If `6` patients are suffering from the disease, then the probability that only three will die is

Options

A. `1458xx10^(-5)`
B. `1458xx10^(-6)`
C. `41xx10^(-6)`
D. `8748xx10^(-5)`

Answer

A

Explanation

`(a)` Probability of disease is fatal `=p=10%`
`p=(10)/(100)=(1)/(10)`, `q=(9)/(10)`
Number of patients `=6`, Number of die cases `=3`
`:.` Probability that `3` will die
`="^(6)C_(3)((1)/(10))^(3)((9)/(10))^(3)=1458xx10^(-5)`