Home
Class 11
MATHS
The extremities of latus rectum of a par...

The extremities of latus rectum of a parabola are (1, 1) and `(1,-1)` . Then the equation of the parabola can be (a)`y^2=2x-1` (b) `y^2=1-2x` (c)`y^2=2x-3` (d) `y^2=2x-4`

Promotional Banner

Similar Questions

Explore conceptually related problems

Find the extremities of latus rectum of the parabola y=x^(2)-2x+3

The ends of the latus rectum of the parabola (x-2)^(2)=-6(y+1) are

Equation of the latus rectum of the parabola 2y^(2) = 5x is

The equation of a parabola is (x+y-2)^(2)=sqrt(2)(x-y) then Vertex of the parabola is (1,1)

The vertex of the parabola (y-2)^(2)=16(x-1) is (1,2) b.(-1,2)c(1,-2)d.(2,1)

The length of the latus rectum of the parabola y^(2)+8x-2y+17=0 is 2 b.4 c.8 d.16

The equation of the directrix of the parabola y^(2)+4y+4x+2=0 is x=-1( b) x=1x=-(3)/(2)(d)x=(3)/(2)

The length of latus rectum of the parabola 4y^(2)+2x-20y+17=0 is (a) 3(b)6(c)(1)/(2) (d) 9