`int(3x^2+1)/((x^2-1)^3) dx`

int (1+3x^2)/(x(1+x^2)) dx

int_(2)^(4) (3x^(2)+1)/((x^(2)-1)^(3))dx = (lambda)/(n^(2)) where lambda, n in N and gcd(lambda,n) = 1 , then find the value of lambda + n

int(3x^(2)+1)/(x(x^(2)+1))dx

int(2x^2+3)sqrt(x+2)\ dx (ii) int(x^2+3x+1)/((x+1)^2)\ dx

int(3x+2)/((x-1)(2x+3))dx

Evaluate : (i) int(3x^(2))/((1+x^(6)))dx (ii) int(x^(3))/((x^(2)+1)^(3))dx (iii) (x^(8))/((1-x^(3))^(1//3))dx

" () "int(3x+2)/((x^(2)+2x+1))dx

int(3x+1)/((x-2)^2(x+2))dx

int (3x+1)/((x-1)^(2)(x+3))dx=