A stone projected from ground level falls on the ground after "4" seconds.Then the height of the stone 1 second after the projection is `(g=10m/s^(2))`

A ball is thrown vertically upwards from the top of a tower with a velocity of 10m/s. If the ball falls on the ground after 5 seconds, the height of the tower will be? (use g=10m/ s^(2) )

A stone is dropped from the top of a tower. If it hits the ground after 10 seconds, what is the height of the tower?

balloon is rising vertically up with a velocity of 29 m/s. A stone is dropped from it and it reaches the ground in 10 seconds. The height of the balloon when the stone was dropped from it is (g = 9.8 m/s^2)

A stone projected at angle theta with horizontal from the roof of a tall building falls on the ground after three seconds. Two second after the projection it was again at the level of projection. Then the height of the building

A stone is projected from the ground with a velocity of 14 ms ^(-1). One second later it clears a wall 2m high. The angle of projection is (g = 10 ms ^(-2))

A particle projected from ground moves at angle 45^(@) with horizontal one second after projection and speed is minimum two seconds after the projection The angle of projection of particle is [ Neglect the effect of air resistance )

A stone is projected horizontally with a velocity 9.8 ms ^(-1) from a tower of height 100 m. Its velocity one second after projection is (g = 9.8 ms ^(-2)).

A stone projected at angle 'theta' with horizontal from the roof of a tall building talls on the ground after three second. Two second after the projection it was again at the level of projection. Then the height of the building is -

A body projected up reaches a point A in its path at the end of 4^( th) second and reaches the ground after 5 seconds from the start.The height of A above the ground is (g=10ms^(-2)) in m