The electrical resistance in ohms of a certain thermometer varies with temperature according to the approximate law:
`R = R_(0) [1 + alpha (T - T_(0))]`
The resistance is `101.6 Omega` at the triple-point of water `273.16 K , " and " 165.5 Omega` at the normal melting point of lead `(600.5 K)`. What is the temperature when the resistance is `123.4 Omega`?

Options

A. `R = a e^(b//T)`
B. `R = a e^(b // T_(2))`
C. `R = ae^(b//T)`
D. `R = a e^(h// sqrtT)`

Answer

C