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Atomic mass number of an element is 232 ...

Atomic mass number of an element is 232 and its atomic number is 90 . The end of radioactive disintegration we obtain an isotope of lead with A = 208 and Z = 82 . Then the number of emitted alpha and beta particles are

A

`alpha = 5 , beta = 4`

B

`alpha = 5 , beta = 5`

C

`alpha = 6 , beta = 4`

D

`alpha = 4 , beta = 6`

Text Solution

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The correct Answer is:
C
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