A groups metal (A) which is present in common salt reacts with (B) to give compound in which hydrogen is present in -1 oxidation state. (B) on reaction with a gas (C) to i universal solvent (D). The compound (D) on reacts with (A) to give (E), a strong base Identify A, B, C, D and E. Explain the reactions.

Explanation

(i) Group (1) metal (A) is present in common salt NaCl. So, (A) is sodium Na.
(ii) Sodium reacts with hydrogen (B) to give sodium hydride-Nal (C) in which hydrogen is in-1 oxidation state.
`2Na+H_(2)to2NaH`
Sodium (A) Hydrogen (B) Sodium hydride (C)
(iii) Hydrogen on reaction with oxygen (0,) gas which is (C) to give a universal solvent water(D).
`2H_(2)+O_(2)underset(2H_(2)O)to`
Water (iv) Water (D) reacts with sodium metal (A) to give a strong base sodium hydroxide NaOH which is (E).
`2Na+ 2H_(2)Oto2NaOH+H_(2)`