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1 mole of an ideal gas, maintained at 4.1 atm and at a certain temperature , absorbs heat 3710 J and expands to 2 litres . Calculate the entropy changes in expansion process.

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Pressure of an ideal gas =`P_i` = 4.1 atm.
Expansion in volume `DeltaV` = 2 litres
Heat absorbed =q = 3710 J
Entropy change = `DeltaS` = ?
For an ideal gas PV = RT for one mole .
`T=(PV)/R=(4.1xx2)/0.0830=100^@C`
T=100+273 = 373 K
`DeltaS=q/T_((K))=3710/373`
Entropy change =9.946 `JK^(-1)`
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