The present ages for Seeta and Geeta are in the ratio 3:4. The product of their ages (in years) is 48. Find the sum of their ages (in years).

Options

A. 7
B. 21
C. 14
D. 28

Answer

C

Explanation

Let the age of Seeta be 3x and the age of Geeta be 4x.
`4x xx 3x = 48 rArr 12x^(2) = 48 rArr x =2`
Seet's age = 6y and Geet's age = 8 years
`therefore ` The sum of their ages = 14 years
Hence, the correct options is (c).