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What will be the units digit of the squa...

What will be the units digit of the squares of the following numbers?

A

71

B

669

C

2533

D

30827

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The correct Answer is:
To find the units digit of the squares of the given numbers, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Units Digit of Each Number:** - For each number, we need to look at the last digit (units digit). 2. **Square the Units Digit:** - Once we have the units digit, we will square it to find the units digit of the square of the original number. 3. **Determine the Units Digit of the Result:** - The units digit of the squared result will be our answer for each number. ### Let's Solve the Given Numbers: 1. **For 71:** - Units digit = 1 - Square of 1 = \(1^2 = 1\) - Units digit of the square = 1 2. **For 669:** - Units digit = 9 - Square of 9 = \(9^2 = 81\) - Units digit of the square = 1 (since the last digit of 81 is 1) 3. **For 2533:** - Units digit = 3 - Square of 3 = \(3^2 = 9\) - Units digit of the square = 9 4. **For 30827:** - Units digit = 7 - Square of 7 = \(7^2 = 49\) - Units digit of the square = 9 (since the last digit of 49 is 9) ### Final Results: - Units digit of the square of 71 = 1 - Units digit of the square of 669 = 1 - Units digit of the square of 2533 = 9 - Units digit of the square of 30827 = 9 ### Summary of Units Digits: - 71 → 1 - 669 → 1 - 2533 → 9 - 30827 → 9

To find the units digit of the squares of the given numbers, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Units Digit of Each Number:** - For each number, we need to look at the last digit (units digit). 2. **Square the Units Digit:** ...
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PEARSON IIT JEE FOUNDATION-SQUARES AND SQUARE ROOTS AND CUBES AND CUBE ROOTS -Level1
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