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Find the value of 3sqrt(6075)xx3sqrt(889...

Find the value of `3sqrt(6075)xx3sqrt(88935s)xx3sqrt(9625)`

A

17355

B

17255

C

17315

D

17325

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The correct Answer is:
To find the value of \( 3\sqrt[3]{6075} \times 3\sqrt[3]{88935} \times 3\sqrt[3]{9625} \), we will follow these steps: ### Step 1: Prime Factorization We will start by finding the prime factorization of each number. **Prime Factorization of 6075:** 1. The last digit is 5, so divide by 5: \[ 6075 \div 5 = 1215 \] 2. The last digit of 1215 is also 5, so divide by 5 again: \[ 1215 \div 5 = 243 \] 3. Now, divide 243 by 3 (since the sum of the digits \(2 + 4 + 3 = 9\) is divisible by 3): \[ 243 \div 3 = 81 \] 4. Divide 81 by 3: \[ 81 \div 3 = 27 \] 5. Divide 27 by 3: \[ 27 \div 3 = 9 \] 6. Divide 9 by 3: \[ 9 \div 3 = 3 \] 7. Finally, divide 3 by 3: \[ 3 \div 3 = 1 \] Thus, the prime factorization of 6075 is: \[ 6075 = 5^2 \times 3^5 \] **Prime Factorization of 88935:** 1. The last digit is 5, so divide by 5: \[ 88935 \div 5 = 17787 \] 2. The sum of the digits of 17787 is \(1 + 7 + 7 + 8 + 7 = 30\), which is divisible by 3: \[ 17787 \div 3 = 5929 \] 3. The number 5929 is \(77^2\) (since \(77 \times 77 = 5929\)), and \(77 = 7 \times 11\): \[ 5929 = 7^2 \times 11^2 \] Thus, the prime factorization of 88935 is: \[ 88935 = 5^1 \times 3^1 \times 7^2 \times 11^2 \] **Prime Factorization of 9625:** 1. The last digit is 5, so divide by 5: \[ 9625 \div 5 = 1925 \] 2. Divide 1925 by 5: \[ 1925 \div 5 = 385 \] 3. Divide 385 by 5: \[ 385 \div 5 = 77 \] 4. As noted before, \(77 = 7 \times 11\). Thus, the prime factorization of 9625 is: \[ 9625 = 5^3 \times 7^1 \times 11^1 \] ### Step 2: Combine the Prime Factors Now we combine the prime factors from all three numbers: \[ 6075 = 5^2 \times 3^5 \] \[ 88935 = 5^1 \times 3^1 \times 7^2 \times 11^2 \] \[ 9625 = 5^3 \times 7^1 \times 11^1 \] Combining these: - For \(5\): \(2 + 1 + 3 = 6\) → \(5^6\) - For \(3\): \(5 + 1 + 0 = 6\) → \(3^6\) - For \(7\): \(0 + 2 + 1 = 3\) → \(7^3\) - For \(11\): \(0 + 2 + 1 = 3\) → \(11^3\) Thus, the combined factorization is: \[ 6075 \times 88935 \times 9625 = 5^6 \times 3^6 \times 7^3 \times 11^3 \] ### Step 3: Calculate the Cube Root Now we can calculate: \[ 3\sqrt[3]{6075} \times 3\sqrt[3]{88935} \times 3\sqrt[3]{9625} = 3^3 \times \sqrt[3]{(5^6 \times 3^6 \times 7^3 \times 11^3)} \] This simplifies to: \[ 27 \times (5^2 \times 3^2 \times 7 \times 11) \] ### Step 4: Final Calculation Calculating the expression: \[ 27 \times (25 \times 9 \times 7 \times 11) \] Calculating step by step: 1. \(25 \times 9 = 225\) 2. \(225 \times 7 = 1575\) 3. \(1575 \times 11 = 17325\) 4. Finally, \(27 \times 17325 = 467775\) Thus, the final value is: \[ \boxed{17325} \]

To find the value of \( 3\sqrt[3]{6075} \times 3\sqrt[3]{88935} \times 3\sqrt[3]{9625} \), we will follow these steps: ### Step 1: Prime Factorization We will start by finding the prime factorization of each number. **Prime Factorization of 6075:** 1. The last digit is 5, so divide by 5: \[ ...
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