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The students of a class wrote an exam. 2...

The students of a class wrote an exam. `20%` of the boys and `30%` of the girls failed in it. The number of boys who passed in it was 30 more than that of girls. A total of 74 students failed in it. Find the strength of the class.

A

280

B

300

C

320

D

260

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The correct Answer is:
To solve the problem step by step, we will define the variables and set up equations based on the information provided in the question. ### Step 1: Define Variables Let: - \( b \) = number of boys in the class - \( g \) = number of girls in the class ### Step 2: Set Up the Equations According to the problem: 1. **Failed Students**: - 20% of boys failed: \( 0.2b \) - 30% of girls failed: \( 0.3g \) - Total students who failed: \( 0.2b + 0.3g = 74 \) This gives us our first equation: \[ 2b + 3g = 740 \quad \text{(Equation 1)} \] 2. **Passed Students**: - Boys who passed: \( 80\% \) of boys = \( 0.8b \) - Girls who passed: \( 70\% \) of girls = \( 0.7g \) - The number of boys who passed is 30 more than the number of girls who passed: \[ 0.8b = 0.7g + 30 \] Rearranging gives us our second equation: \[ 8b - 7g = 300 \quad \text{(Equation 2)} \] ### Step 3: Solve the Equations Now we have two equations: 1. \( 2b + 3g = 740 \) 2. \( 8b - 7g = 300 \) To eliminate one variable, we can multiply Equation 1 by 4: \[ 8b + 12g = 2960 \quad \text{(Equation 3)} \] ### Step 4: Subtract Equation 2 from Equation 3 Now, we subtract Equation 2 from Equation 3: \[ (8b + 12g) - (8b - 7g) = 2960 - 300 \] This simplifies to: \[ 19g = 2660 \] ### Step 5: Solve for \( g \) Now, divide both sides by 19: \[ g = \frac{2660}{19} = 140 \] ### Step 6: Substitute \( g \) back to find \( b \) Now, substitute \( g = 140 \) back into Equation 1: \[ 2b + 3(140) = 740 \] This simplifies to: \[ 2b + 420 = 740 \] Subtract 420 from both sides: \[ 2b = 320 \] Now, divide by 2: \[ b = 160 \] ### Step 7: Find the Total Strength of the Class Now, we can find the total strength of the class: \[ \text{Total strength} = b + g = 160 + 140 = 300 \] ### Final Answer The strength of the class is **300**. ---

To solve the problem step by step, we will define the variables and set up equations based on the information provided in the question. ### Step 1: Define Variables Let: - \( b \) = number of boys in the class - \( g \) = number of girls in the class ### Step 2: Set Up the Equations ...
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