The distance between two railwat stations A and B is 440 km. two trains ` T_(1) and T_(2)` start simultaneously from the stations A and B , respectively , and move twards each other. Then train ` T_(1) and T_(2)` start simultaneouslym from the station A and B respectively, and move towards each other. the train` T_(1)` moves with a constant speed of 60 km` h^(-1)` and the train `T_(2)` moves with a speed of `50 km h^(-1)` , Determine the point where they meet and the time taken for this.

Explanation

Time for which the two trains travel before they meet are equal.
That is `t_(A) =t_(g)`
But `t_(A) = (d_(A))/(S_(A)) ,t_(B) = (d_(B))/ (s_(B))`
Let the two trains meet at a distance of X km from A. then the distance travelled by the other train is ( 440 - x) km

` x/60 = (440-x)/50 Rightarrow 5x = 2640 - 6x`
` Rightarrow 11x- 2640 Rightarrow x = 240 km `
The two trains meet each other at a distance of 240 km from A.
Time taken , `t = (d_(A)) /(s_(A))= 240/60 = 4 h`