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Define the least count of an instrument....

Define the least count of an instrument.

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Statement-I:The length of an object is measured with two instruments as l =4.01cm and l =4.009cm, The second instrument has a better resolution Statement-II: More value is the least count of an instrument, better is the resolution.

19 divisions on the main scale of a vernier callipers coincide with 20 divisions on the vernier scale. If each division on the main scale is of 1 cm , determine the least count of instrument.

The given diagram represents a screw gauge. The circular scale is divided into 50 divisions and the linear scale is divided into millimeters. If the screw advances by 1 mm when the circular scale makes 2 complete revolutions, find the least count of the instrument and the reading of the instrument in the figure. .

A vernier calliper has 20 divisions on the vernier scale. One centimetre on the main scale is divided into 20 equal parts. Find the least count of this instrument.

In a vernier callipers, 1 cm of the main scale is devided into 20 equal parts. 19 divisions of the main scale coincide with 20 divisions on the vernier scale . Find the least count of the instrument.

in an experiment the angles are required to be using an instrument, 29 divisions of the main scale exactly coincide with the 30 divisions of the vernier scale. If the sallest division of the main scale is half- a degree (= 0.5^(@) , then the least count of the instrument is :

In a experiment the angle are required to be measured using an instrument. 26 divisions of the main scale exactly coincide with the 30 divisions of the vernier scale . If the smallest division of the main scale is half -a-degree (=0.5^(@)) then the least count of the instrument is .

N divisions on the main scale of a vernier calliper coincide with (N + 1) divisions of the vernier scale.If each division ofmain scale is 'a’ units, then the least count of the instrument is