Draw the major product formed when 1-ethoxyprop-1-ene is heated with one equivalent of HI

Explanation

This reaction follows `SN^(1)` mechanism because in this reaction the more stable carbocation is formed that is double bonded carbocation. Therefore, the given molecule reacts with HI to form ethanol and 1-iodo prop-1-ene.
`CH_(3)-CH=CH-O-C_(2)H_(5) overset(HI//Delta)(rarr)underset(("1-iodo prop-1-ene"))(CH_(3)-CH=CH-I)+underset(("ethanol"))(C_(2)H_(5)OH)`