The composition of a sample of wurtzite is `Fe_(0.93)O_(1.00)` what `%` of Iron present in the form of `Fe^(3+)`?

Options

A. `16.05%`
B. `15.05%`
C. `18.05%`
D. `17.05%`

Answer

B

Explanation

Hint : Let the number of `Fe^(2+)` ions in the crystal be x
The number of `Fe^(3+)` ions in the crystal be y
Total number of `Fe^(2+) and Fe^(3+)` ions is `x+y`. Given that `x+y=0.93`
The total charge `=0x(2+)+(0.93-x)(+3)-2=0`
`2x+2.97-3x-2=0x=0.79`
`"Percentage of "Fe^(3+)=(((0.93-0.79))/(0.93))100=15.05%`