Radioactive disintegration of `._(88)Ra^(226)`
`Ra overset(-alpha)rarr Rn overset(-alpha)rarr RnA overset(-alpha)rarr RaB overset(-beta)rarr RaC`
Determine the mass number, atomic number, and group in periodic table for `RaC`.

Explanation

Parent element is `._(88)^(226)Ra`.
atomic mass = 226
Atomic number = 88
RaC is formed after the emission of 3 alpha particles. Mass of 3 alpha particles `= 3 xx 4 = 12`
So, Atomic mass of RaC = (226 - 12) = 214
With emission of one `alpha`particle atomic number is decreased by 2 and with the emission of one `beta`-particle, atomic number is increased by 1.
So, Atomic number of RaC = `88 - (3 xx 2) + 1 = 83`