If in 3160 years, a radioactive substance becomes one-fourth of the original amount, find it’s the half-life period.

Explanation

`(N)/(N_(0)) = (1)/(4)`
So, `(1)/(4) = ((1)/(2))^(n)`
or `((1)/(2))^(2) = ((1)/(2))^(n)`
or n = 2
We know that, total time 'T' = `n xx t_(1//2)`
So, `3160 = 2 xx t_(1//2)`
or `t_(1//2) = (3160)/(2) = 1580` years
The half life period of the radioactive substance is 1580 years.