The amount of `._(6)C^(14)` isotope in a piece of wood is found to be one-fifth of that present in a fresh piece of wood. Calculate the age of wood (Half life of `C^(14) = 5577` years)

Explanation

We know that `t = (2.303 xx t_(1//2))/(0.693) log ((N_(0))/(N))`
Given, `N = (N_(0))/(5)`
So, `t = (2.303 xx 5577)/(0.693) log 5`
or `t = (2.303 xx 5577)/(0.693) xx 0.6989 = 12953` years