A piece of wood was found to have `C^(14)//C^(12)` ratio 0.6 times that in a living plant. Calculate that in a living plant. Calculate the period when the plant died. (Half life of `C^(14) = 5760` years)?

Explanation

We know that, `t = (2.303 xx t_(1//2))/(0.693) log ((N_(0))/(N))`
So, `t = (2.303 xx 5760)/(0.693) log (1)/(0.6)`
`= (2.303 xx 5760)/(0.693) xx 0.2201`
= 4213 years