A radioactive nuclide is produced at a constant rate of `alpha` per second . It’s decay constant is `lambda`. If `N_(0)` be the no. of nuclei at time t=0 , then max. no. nuclei possible are :

Options

A. `(alpha)/(lambda)`
B. `N_(0) + (alpha)/(lambda)`
C. `N_(0)`
D. `(lambda)/(alpha) + N_(0)`

Explanation

Maximum number of nuclei will be present when Rate of decay = rate of formation
`lambda N = alpha`
`N = (alpha)/(lambda)`