Find the eccentric angle of a point on the ellipse `(x^2)/6+(y^2)/2=1` whose distance from the center of the ellipse is `sqrt(5)`

The eccentric angle of a point on the ellipse x^(2)/6 + y^(2)/2 = 1 whose distance from the centre of the ellipse is 2, is

Find the eccentric angle of a point on the ellipse x^2 + 3y^2 = 6 at a distance 2 units from the centre of the ellipse.

Number of points on the ellipse x^2/25+y^2/7=1 whose distance from the centre of the ellipse is 2sqrt7 is

The eccentric angle of a point on the ellipse x^2/6 + y^2/2 = 1 whose distance from the centre of the ellipse is 2, is (A) pi/4 (B) 7pi/6 (C) 3pi/2 (D) 5pi/3

The ecentric angle of the points on the ellipse (x^(2))/(6)+(y^(2))/(2)=1 whose distane from its centre is 2 is/are.

There are exactly two points on the ellipse (x^2)/(a^2)+(y^2)/(b^2) =1 whose distance from the centre of the ellipse are equal to sqrt((3a^2-b^2)/(3)) . Eccentricity of this ellipse is