The decomposition of a certain mass of `CaCO_(3)` gave `11.2 dm^(3)` of `CO_(2)` gas at STP. The mass of KOH required to completely neutralise the gas is

Options

A. 56 g
B. 28 g
C. 42 g
D. 20 g

Answer

B

Explanation

Weight of `11.2 dm^(3)` of `CO_(2)` gas at STP is
`44//2=22g`
`underset(56 g)(KOH)+underset(44 g)(CO_(2))to KHCO_(3)`
KOH required for complete neutralisation of 22 g `CO_(2)` is
`(56)/(44)xx22=28 g`.