The formation of `O_(2)""^(+)[PtF_(6)]^(-)` is the basis for the formation of xenon fluorides. This is because

Options

A. `O_(2)` and Xe have comparable sizes
B. both `O_(2)` and Xe are gases
C. `O_(2)` and Xe have comparable ionisation energies
D. `O_(2)` and Xe have comparable electronegativities

Answer

A, C

Explanation

(i) The first ionisation energy of xenon `(1, 170 kJ mol^(-1))` is quite close to that of dioxygen `(1,180 kJ mol^(-1))` .
(ii) Themolecular diameters of xenon and dioxygen are almost identical (400 pm).
Based on the above similarities Barlett (who prepared `O^(2+)[PtF_(6)]^(-)` compound) suggested that since oxygen combines with `PtF_(6)`, so xenon should also form similar compound with `PtF_(6)`.