Volume occupied by single CsCl ion pair in a crystal is `7.014 xx 10^(-23) c^(3)`. The smallest Cs-Cs internuclear distance is equal to length of the side of the cube corresponding to volume of one CsCl ion pair. The smallest Cs to Cs internuclear distance is nearly

Options

A. 4.4Å
B. 4.3Å
C. 4Å
D. 4.5 Å

Answer

C

Explanation

Volume of `CsCl=a^(3)`
`7.014xx10^(-23)cm^(3)=a^(3)` ( a = edge length)
`a= root3(7.014xx10^(-23))`
`a=4.12xx10^(-8)cm=4.12 Å ~~4Å`