A sine wave has an amplitude A and wavelength `lambda`. Let V be the wave velocity and v be the maximum velocity of a particle in the medium. Then

Options

A. `V= v " if " lamda = (3A)/(2pi)`
B. `V= v " if " A = 2pi lamda`
C. `V= v " if "A = (lamda)/(2pi)`
D. V can not be equal to v

Answer

C

Explanation

Maximum particle velocity, `v= A omega = 2pi v A` But `V= v lamda`
If V= v then, then `v lamda = 2pi v A or lamda = 2pi A`