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Three resistances of values 2Omega, 3Ome...

Three resistances of values `2Omega, 3Omega and 6Omega` are to be connected to produce an effective resistance of `4Omega`. This can be done by connecting

A

`2Omega` resistance in parallel with the parallel combination of `3Omega and 6Omega`

B

`2Omega` resistance in series with the parallel combination of `3Omega and 6Omega`

C

`3 Omega` resistance in series with the parallel combination of `2Omega and 6Omega`

D

`6Omega` resistance in series with the parallel combination of `2Omega and 3Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
Parallel combination of `3Omega and 6Omega`
`=(6 xx 3)/(6 +3) = 2Omega`
`:. 2Omega` is to connected in series to parallel combination of `3Omega and 6Omega`
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