A charged particle is moving in a magnetic field of strength B perpendicular to the direction of the field.If q and m denote the charge and mass of the particle respectively, then the frequency of rotation of the particle is

Options

A. `f =(qB)/(2 pi m)`
B. `f =(qB)/(2 pi m^(2))`
C. `f = (2 pi^(2)m)/(qB)`
D. `f = (2pim)/(qB)`

Answer

A

Explanation

Lorentz force is the centripetal force, Bqv Centrifugal force = `(mv^(2))/(R)`
`therefore Bqv = (mv^(2))/(R)` or `Bq = m((v)/(R))`
or `Bq = m omega` or `Bq = m xx 2pif`
or `f = (qB)/(2pim)`