The current passing through the ideal ammeter in the circuit given below is

Options

A. `1.25` A
B. `1` A
C. `0.75` A
D. `0.5` A.

Answer

D

Explanation

`2 Omega` and `2 Omega` in parallel give` (2xx2)/(2 + 2) = 1 Omega`
`therefore` Total resistance = 1 + 2 + 1 + 4 = 8`Omega`.
`therefore` ` Current = -("emf")/("resistance")` = `(4)/(8) = 0.5 A`