In a reverse biased diode when the applied voltage changes by 1 V, the current is found to change by `0.5 muA`. The reverse bias resistance of the diode is

Options

A. `2 xx 10^(5) Omega`
B. `2 xx 10^(6) Omega`
C. `200 Omega`
D. `2 Omega`

Answer

B

Explanation

Reverse resistance
`= (Delta V)/(Delta I) = (1)/(0.5 xx 10^(-6)) = 2 xx 10^(6) Omega`