The kinetic energy of an electron gets tripled, then thede Broglie wavelength associated with it changes by a factor

Options

A. `1/3`
B. `sqrt(3)`
C. `1/(sqrt(3))`
D. `3`

Answer

C

Explanation

For an electron
de Broglie wavelength `lamda=h/(sqrt(2mK))`
where h= Planck's constant m= mass of an electron K=kinetic energy of an electron
Since h,m remains the same `:. lamda prop 1/(sqrt(K))`
`implies(lamda)/(lamda')=sqrt((K')/K)=sqrt((3K)/K)` or `lamda'=(lamda)/(sqrt(3))`