A body of mas 0.05 kg is observed to fall with an acceleration of `9.5 ms^(-2)`. The opposing force of air on the body is ……………… (`g=9.8ms^(-2)`)

Options

A. 0.015 N
B. 0.15 N
C. 0.030 N
D. zero

Answer

A

Explanation

Here mass of the body
`m=0.05kg`
Acceleration `a=9.5ms^(-2),g=9.8ms^(-2)`
`:.mg-f_("air")=ma`
or `f_("air")=m(g-a)`
`=0.05(9.8-9.5)`
`=0.015N`