A resistor and a capacitor are connected in series with an a.c. source. If the potential drop across the capacitor is 5 V and that across resistor is 12 V, the applied voltage is

Options

A. 13 V
B. 17 V
C. 5 V
D. 12 V

Answer

A

Explanation

Let the applied voltage be V volt.
Here `V_(R)=12V,V_(C)=5V`
`V=sqrt(V_(R)^(2)+V_(C)^(2))=sqrt((12)^(2)+(5)^(2))`
`=sqrt(144+25)=sqrt(169)=13V`