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A galvanometer of resistance 240Omega al...

A galvanometer of resistance `240Omega` allows only 4% of the main current after connecting a shunt resistance. The value of the shunt resistance is

A

`10Omega`

B

`20 Omega`

C

`8 Omega`

D

`5Omega`

Text Solution

Verified by Experts

The correct Answer is:
A


Here galvanometer resistance `G=240Omega`
Shunt resistnace S=?
`I_(G)=4/100I`
From figure `(I-I_(G))S=I_(G)G`
`(I_(4I)/100)S=(4I)/100xx240`
or `S=(4xx240)/96=10Omega`
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