The charge deposited of `4 muF` capacitor in the cirucuit is

Options

A. `6xx10^(-6)C`
B. `12xx10^(-6)C`
C. `24xx10^(-6)C`
D. `36xx10^(-6)C`

Answer

C

Explanation

As the capacitors `4 muF` and `2muF` connected in parallel, are in series with `6muF` capacitor, their equivalent capacitance is `((2+4)xx6)/(2+4+6)=3muF`
Charge in the circuit `Q=3muFxx12V=36muC`

Since the capacitors `4muF` and `2muF` are connected in paralle, therefore potential difference across them is same.
`implies(Q_(1))/(Q_(2))=(C_(1))/(C_(2))=4/2` ro `Q_(1)=2Q_(2)`
Also `Q=Q_(1)+Q_(2)`
`:.36muC=2Q_(2)+Q_(2)`
or `Q_(2)=(36muC)/3=12muC`
`Q_(1)=Q-Q_(2)=36muC-12muC`
`=24muC=24xx10^(-6)C`