The figure shows the energy level of certain atom. When the electron deexcites from 3E to E, an electromagnetic wave of wavelength `lamda` is emitted. What is the wavelength of the electromagnetic wave emitted when the electron de excites from `(5E)/(3)` to E?

Options

A. `3 lamda`
B. `2 lamda`
C. `5 lamda`
D. `(3 lamda)/(5)`

Answer

A

Explanation

From figure,
`(hc)/(lamda) = 3E-E=2E`…(i)
`(hc)/(lamda') = (5E)/(3) -E= (2)/(3)E` …(ii)
Divide (i) by (ii), we get
`(lamda')/(lamda) = 3 or lamda' = 3 lamda`