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If there is no torsion in the suspension...

If there is no torsion in the suspension thread, then the time period of a magnet executing SHM is

A

`T = 1/(2pi) sqrt((I)/(MB))`

B

`T = 2pi sqrt((MB)/(I))`

C

`T = 1/(2pi) sqrt((MB)/I)`

D

`T = 2pi sqrt(I/(MB))`

Text Solution

Verified by Experts

The correct Answer is:
D
The time period of a ma gnet executing SHM is
`T = 2pi sqrt((I)/(MR))`
where I is the moment of inertia of the magnet , M is its magnetic moment and B is an external magnetic field
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