If `epsilon_(0)` and `mu_(0)` are the permittivity and permeability of free space and are the corresponding quantities for a medium, then refractive index of the medium is

Options

A. `sqrt((mu_(epsilon))/(mu_(0)epsilon_(0)))`
B. insufficient information
C. `sqrt((mu_(0)epsilon_(0))/(muepsilon))`
D. 1

Answer

A

Explanation

Refractive index of the medium is
` n = (c("speed of light in vacuum"))/(v("speed of light in medium ")) `
But ` c = 1/(sqrt(mu_(0)epsilon_(0))) and v = 1/(sqrt(muepsilon ))`
` :. " " n = (1/(sqrt(mu_(0)epsilon_(0))))/(1/(sqrt(muepsilon ))) = sqrt((muepsilon)/(mu_(0)epsilon_(0)))`