The ratio of the dimensions of Planck constant and that of moment of inertia has the dimensions of

Options

A. frequency
B. velocity
C. time
D. angular momentum

Answer

A

Explanation

As planck constnt (h) = `("energy ")/("frequency")`
and moment of inertia `(I) = mass xx ("radius of gyration ")^(2)`
` :. [h ] = ([ML^(2)T^(-2)])/([T^(-1)] ) = [ML^(2)T^(-1)] `
and `[I] = [M][L^(2)] = [ML^(2)T^(0)] `
Their corresponding ratio is
`([h])/([I]) = ([ML^(2)T^(-1)])/([ML^(2)T^(0)]) = [T^(-1) ] =" [frequency ]"`