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A stone of mass 0.05 kg is thrown vertic...

A stone of mass 0.05 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion?

A

`0.49` N vertically downwards

B

`9.8` N vertically downward

C

`0.49` N vertically upwards

D

`0.98 ` N vertically downwards

Text Solution

Verified by Experts

The correct Answer is:
A
Here , Mass of the stone , m = 0.5 kg
The magnitude of net force on the stone is `F=mg=(0.05kg)(9.8ms^(-2))=0.49N` Its direction is vertically downwards.
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Knowledge Check

  • A stone of mass 0.005 kg is thrown vertically upwards. What is the direction and magnitude of net force on the stone during its upward motion ?

    A
    0.049 N vertically downwards
    B
    9.8 N vertically downwards
    C
    0.49 N vertically upwards
    D
    0.98 N vertically downwards.

  • A particle of mass 100 g is thrown vertically upwards with a speed of 5 m/s. The work done by the force of gravity during the time the particle goes up is:

    A
    `-0.5 J`
    B
    `-1.125 J`
    C
    `1.25 J`
    D
    0.5 J

  • A body of mass 1 kg is thrown vertically upwards with initial K.E. of 98 joule. The height at which its energy is reduced to half will be

    A
    2.5 m
    B
    1.25 m
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