Three resistances `2 Omega , 3 Omega and 4 Omega ` are connected in parallel . The ratio of currents passing through them when a potential differences is applied across its ends will be

Options

A. `6:4:3`
B. `4:3:2`
C. `6:3:2`
D. `5:4:3`

Answer

A

Explanation

When resistance are connected in parallel ,
`I prop 1/R`
` :. I_(1) : I_(2) :I_(3) = 1/(R_(1) : 1/(R_(2) ) : 1/(R_(3))`
` = 1/2 : 1/3 : 1/4 = 12/2 : 12/3 : 12/4 = 6:4:3 `