A Carnot engine takes 300 calories of heat from a source at 500 K and rejects 150 calories of heat to the sink. The temperature of the sink is

Options

A. 125 K
B. 250 K
C. 750 K
D. 1000 K

Answer

B

Explanation

Here,Temperture of the source , `T_1 = 500 K`
Heat taken from the source, `Q_1 = 300 cal`
Heat rejected to the sink , `Q_2=150 cal`
Temperature o the sink , `T_2=?`
As `T_1/T_2=Q_1/Q_2" ":.T_2=Q_2/Q_1T_1`
or `T_2=((150 " cal")/(300 " cal"))(500 K)=250K`