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The total energy of an electron revolvin...

The total energy of an electron revolving in the second orbit of hydrogen atom is

A

`-13.6` eV

B

`-1.51` eV

C

`-3.4` eV

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
The total energy of an electron revolving the `n^(th)` orbit of hydrogen atom is
`E_n=-(13.6)/n^2eV`
For the second orbit , n = 2
`:.E_2=(13.6)/2^2eV=-3.4eV`
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