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In the figure below, bar(BC)|| bar(EF),B...

In the figure below, `bar(BC)|| bar(EF),BC=EF ` and `DF =AC`. Which of the following congurency axiom(s) is`//` are suitable to prove that `Delta BCA =Delta EFD` ?

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The correct Answer is:
D

(i) `/_ EFD` and `/_ ACB` , are alternate angles, so they are equal.
(ii) Given `DF=AC` and `EF=BC`.
(iii) Conclude which congruency property is applicable.
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