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In the above diagram (not to scale), AB=...


In the above diagram (not to scale), `AB=AC=`. O is the centre of the circle. If `/_ ABC =80^(@)`, then `/_ BOC =`

A

`20^(@)`

B

`40^(@)`

C

`60^(@)`

D

`80^(@)`

Text Solution

Verified by Experts

The correct Answer is:
b
(i) Angle subtended by a chord at the centre of a circle is twice the angle subtended by it at any point on he circumference in the same segment in which the centre lies.
(ii) ABC is an isosceles triangle, `i.e., /_ ABC= /_ BCA`, using this find `/_BAC`.
(iii) Then use the property that angle made by an arc at the centre of the circle is double the angle made by the same arc at any point on the remaining part of the circle.
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