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In the given figure, `/_DBA=2 /_DAB = 4/_ CAD`.
If `/_ ADC =120^(@)` , then the angle made by AB at the centre of the circle is

A

`20^(@)`

B

`40^(@)`

C

`60^(@)`

D

`80^(@)`

Text Solution

Verified by Experts

The correct Answer is:
d
(i) Consider `/_CAD` as x, then `/_ DAB =2x` and `/_DBA =4x`, using these angles and find `/_ACB`.
(ii) Angle made by arc AB at the centre of the circle `=2 /_ ACB`.
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