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In the above figure , O is the centre of...


In the above figure , O is the centre of the circle, AB and CD are diameters. `/_ COB =50^(@)=50^(@)` . If E is the midpoint of AF, then find `/_ ADF`

A

`130^(@)`

B

`100^(@)`

C

`110^(@)`

D

`120^(@)`

Text Solution

Verified by Experts

The correct Answer is:
a
`/_ COB= /_ AOD =50^(@)` (Vertically opposite angles ).
Since E is the mid-point of AF,`/_ OEA = /_ OEF=90^(@)`.
`implies /_OAE =/_OFE =40^(@)`
`implies /_DOF =50^(@)`
`:. /_ADF =1//2 `( reflex `( /_AOF) =130^(@)`
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